Anu0408
Question 11:- Triangle ABD and ∆ ECF are right angled triangles at angle D and angle F respectively, also since in ∆ABC AB = AC therefore by isosceles triangle theorem angle B= angle C therefore in both the triangles ABD and ECF angle B=angle C , therefore by A-A test for similarity, ∆ABD is similar to ∆ECF i.e ∆ABD~∆ECF
Answers & Comments
i.e ∆ABD~∆ECF