Give that DE is // to BC
⇒ ΔADE is similar to ΔABC
Find AC:
By property of similar triangle:
Find EC:
AC = AE + EC
10.5 = 3 + EC
EC = 10.5 - 3
EC = 7.5 cm
Answer: EC is 7.5 cm
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Answers & Comments
angle A = angle A
angleD= angle B(because DE//BC)
angleE=angle C
therefore the triangles are similar by AAA similarity criteria.
thus
AD/AE=AE/AC
AD/AD+BD=AE/EC+AE
2/7=3/3+EC
3+EC=3*7/2=21/2=10.5
EC=10.5-3=7.5
thus
EC =7.5cm
Give that DE is // to BC
⇒ ΔADE is similar to ΔABC
Find AC:
By property of similar triangle:
Find EC:
AC = AE + EC
10.5 = 3 + EC
EC = 10.5 - 3
EC = 7.5 cm
Answer: EC is 7.5 cm