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anugyasoni
@anugyasoni
June 2022
1
23
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plz help me in these two questions. i have practised for 2 hours bt could not get the answer
plz plz plz help me
Answers & Comments
ani99ket
Product = -p(p+1)
sum = -1
thus roots can be simply taken out as
p and -(p+1) becuase these satisfy the criteria.
similarly you can take out the roots of second question which are
m and -(m+3)
or do it this way
let the roots be a and b
thus a*b = -p(p+1)
a+b=-1
a=-1-b
therfore
b(-1-b) =-p(p+1)
-b(1+b) = -p(p+1)
thus b =p
and a =-(1+p).
1 votes
Thanks 1
MilitheQUORAN
can - (x+1) be its root too??
ani99ket
x is a variable you need to find the x...
ani99ket
-(x+1) as a root of a polynomial in x doesn't makes any sense
MilitheQUORAN
okh! Thank you
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Answers & Comments
sum = -1
thus roots can be simply taken out as
p and -(p+1) becuase these satisfy the criteria.
similarly you can take out the roots of second question which are
m and -(m+3)
or do it this way
let the roots be a and b
thus a*b = -p(p+1)
a+b=-1
a=-1-b
therfore
b(-1-b) =-p(p+1)
-b(1+b) = -p(p+1)
thus b =p
and a =-(1+p).