Answer:
Let Radius =R,and ,OD=(R-2)
Join ,OA And,OB ,AO =R
Hence Triangle,(AOD) is Right Triangle,
{WHERE AB =12CM ,AND AD=AB/2=12/2=6CM}
Using Pythagoras Theorem,
=>AO²=OD²+AD²
=>R²=(R-2)²+6²
=>R² =R²+4-4R+36
=>R²-R²=40-4R
=>4R=40
=>R=40/4=10CM
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Answers & Comments
LET RADIUS=R,AND ,OD=(R-2)
JOIN ,OA AND,OB ,AO =R
HENCE TRIANGLE,(AOD) IS RIGHT TRIANGLE,
{WHERE AB =12CM ,AND AD=AB/2=12/2=6CM}
USING PYTHAGORAS THEOREM,
=>AO²=OD²+AD²
=>R²=(R-2)²+6²
=>R² =R²+4-4R+36
=>R²-R²=40-4R
=>4R=40
=>R=40/4=10CM
I HOPE ITS HELP YOU DEAR:-)
Answer:
Let Radius =R,and ,OD=(R-2)
Join ,OA And,OB ,AO =R
Hence Triangle,(AOD) is Right Triangle,
{WHERE AB =12CM ,AND AD=AB/2=12/2=6CM}
Using Pythagoras Theorem,
=>AO²=OD²+AD²
=>R²=(R-2)²+6²
=>R² =R²+4-4R+36
=>R²-R²=40-4R
=>4R=40
=>R=40/4=10CM