given, initial velocity = 10 m/s time taken = 1.2 sec acceleration = 9.8 m/s^2 therefore distance, s = ut+1/2 at^2 s= 10*1.2 + 1/2 * 9.8 * (1.2 )^2 s = 12 + 4.9 * 1.44 s = 12 + 7.056 s = 19.056 therefore option (d) 19 m is the answer according to me. i hope that this will help u.....................^_^
Answers & Comments
Verified answer
given,initial velocity = 10 m/s
time taken = 1.2 sec
acceleration = 9.8 m/s^2
therefore distance,
s = ut+1/2 at^2
s= 10*1.2 + 1/2 * 9.8 * (1.2 )^2
s = 12 + 4.9 * 1.44
s = 12 + 7.056
s = 19.056
therefore option (d) 19 m is the answer according to me.
i hope that this will help u.....................^_^