Answer:
the answer is please mark as brailiest please please
In ΔAYB and ΔAXC
AX=AY (given)
∠ACX=∠ACY (AX=AY)
∠BAC=∠BAC (common)
so, ΔAYB≅ΔAXC (by ASA congruene)
now,
CX=BY (cpct)
hence proved
hope it helps
mark as brainliest
or
the picture in the attachment is just for your additional answer
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Answer:
the answer is please mark as brailiest please please
Verified answer
Answer:
In ΔAYB and ΔAXC
AX=AY (given)
∠ACX=∠ACY (AX=AY)
∠BAC=∠BAC (common)
so, ΔAYB≅ΔAXC (by ASA congruene)
now,
CX=BY (cpct)
hence proved
hope it helps
mark as brainliest
or
the picture in the attachment is just for your additional answer