The stone is thrown upward from height,h= 85m from the ground.
If reaches the ground in 5sec.
Let the initial velocity be 'u'.
The displacement is '-85m' & acceleration is '-10m/s^2 as they are downward so the negative sign comes.
At the greatest height the ground, the stone comes to momentary rest. That means it's velocity becomes zero.
Using,
Thus, the maximum height from the ground is 3.2 + 85= 88.2m
v= u+ at
=) v= 8- 10×5
=) v= 8-50
=) v= -42m/s [downward]
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The stone is thrown upward from height,h= 85m from the ground.
If reaches the ground in 5sec.
Let the initial velocity be 'u'.
The displacement is '-85m' & acceleration is '-10m/s^2 as they are downward so the negative sign comes.
Using,
At the greatest height the ground, the stone comes to momentary rest. That means it's velocity becomes zero.
Using,
Thus, the maximum height from the ground is 3.2 + 85= 88.2m
Velocity with which it reaches the ground is,
v= u+ at
=) v= 8- 10×5
=) v= 8-50
=) v= -42m/s [downward]
hope it helps ☺️