mamu9
X-3y=4 slope=1/3 the equation of the line y-y1 =m (x-x1) y+3=1/3( x-5) 3y+9=x-5 3y- x+14= 0 ...........is the required equation hope it helps
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afridi7
Given eqn is 3y=x-4 y =[1/3]x -[4/3] we know that Y =mx+b hence slope = m°= 1/3 since both lines are parallel, hence m=m°=1/3=slope of another line to find ewuation of line with slope m and passing through point (5,-3)
(Y-Y°)=m(X-X°) given Y°= -3 and X° = 5„ m = 1/3 then (Y+3)= 1/3(X-5) 3y+9= X-5 X-3y-14=0
Answers & Comments
slope=1/3
the equation of the line
y-y1 =m (x-x1)
y+3=1/3( x-5)
3y+9=x-5
3y- x+14= 0 ...........is the required equation
hope it helps
3y=x-4
y =[1/3]x -[4/3]
we know that Y =mx+b
hence slope = m°= 1/3
since both lines are parallel, hence
m=m°=1/3=slope of another line
to find ewuation of line with slope m and passing through point (5,-3)
(Y-Y°)=m(X-X°)
given Y°= -3 and X° = 5„ m = 1/3
then
(Y+3)= 1/3(X-5)
3y+9= X-5
X-3y-14=0