Given: PQ || DE
Proof:
In both the triangles,
DE || PQ (given)
So,
angle FDE = angle FPQ (CORRESPONDING ANGLES)
angle DEF = angle PQF (CORRESPONDING ANGLES)
So, by AA Similarity, triangle DEF ~ triangle PQF
Since, triangle DEF ~ triangle PQF,
By solving, we get
DE = 3 x 1.8 = 5.4
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Answers & Comments
Given: PQ || DE
Proof:
In both the triangles,
DE || PQ (given)
So,
angle FDE = angle FPQ (CORRESPONDING ANGLES)
angle DEF = angle PQF (CORRESPONDING ANGLES)
So, by AA Similarity, triangle DEF ~ triangle PQF
Since, triangle DEF ~ triangle PQF,
By solving, we get
DE = 3 x 1.8 = 5.4
So, DE = 5.4cm
DP = 3.1cm