3. Assuming constant acceleration, the speed at 14 seconds can be found using the formula:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Assuming the initial velocity is 4 m/s (at time 0), the acceleration can be calculated as:
a = (v - u)/t = (v - 4)/14
If we assume the acceleration is constant, we can use the average speed over the time interval to find the final velocity:
v = u + at = 4 + a(14) = 4 + (v - 4)/14 * 14
Solving for v, we get:
v = 62 m/s
Therefore, assuming constant acceleration, the speed at 14 seconds would be 62 m/s.
4. To find the time at which the object reaches a speed of 45m/s, we need to look at the graph and see where the speed curve intersects the line for 45 m/s. From the graph, we can see that the object reaches a speed of 45 m/s at around 32 seconds.
5. The object's acceleration can be calculated using the formula:
a = (v-u)/t
where v is the final velocity, u is the initial velocity, and t is the time interval. Using the values from the graph, we can calculate the acceleration between time 0 and 2 seconds:
a = (6 - 4)/(2 - 0) = 1 m/s^2
Since the acceleration is constant, this value should hold for the entire time interval.
6. If the speed of the object is maintained at 50m/s from 10s to 20s, the graph would be a horizontal line at y = 50m/s for the corresponding time interval.
7. Since the speed is constant (i.e., no change in speed), the acceleration during this interval is zero.
8. If the speed of the object decreased from 50m/s at 20s to 30m/s at 40s, the graph would show a downward sloping line between 20s and 40s. The shape of the graph would be linear (i.e., a straight line).
Answers & Comments
Verified answer
Answer:
1. As time increases, the speed also increases.
2. At 5 seconds, the speed is 8 m/s.
3. Assuming constant acceleration, the speed at 14 seconds can be found using the formula:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Assuming the initial velocity is 4 m/s (at time 0), the acceleration can be calculated as:
a = (v - u)/t = (v - 4)/14
If we assume the acceleration is constant, we can use the average speed over the time interval to find the final velocity:
v = u + at = 4 + a(14) = 4 + (v - 4)/14 * 14
Solving for v, we get:
v = 62 m/s
Therefore, assuming constant acceleration, the speed at 14 seconds would be 62 m/s.
4. To find the time at which the object reaches a speed of 45m/s, we need to look at the graph and see where the speed curve intersects the line for 45 m/s. From the graph, we can see that the object reaches a speed of 45 m/s at around 32 seconds.
5. The object's acceleration can be calculated using the formula:
a = (v-u)/t
where v is the final velocity, u is the initial velocity, and t is the time interval. Using the values from the graph, we can calculate the acceleration between time 0 and 2 seconds:
a = (6 - 4)/(2 - 0) = 1 m/s^2
Since the acceleration is constant, this value should hold for the entire time interval.
6. If the speed of the object is maintained at 50m/s from 10s to 20s, the graph would be a horizontal line at y = 50m/s for the corresponding time interval.
7. Since the speed is constant (i.e., no change in speed), the acceleration during this interval is zero.
8. If the speed of the object decreased from 50m/s at 20s to 30m/s at 40s, the graph would show a downward sloping line between 20s and 40s. The shape of the graph would be linear (i.e., a straight line).
Explanation:
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Answer:
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Explanation:
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