In a perfectly elastic collision, both momentum and kinetic energy are conserved. The formula for the final velocity of Ball B after an elastic collision is given by:
vf=2x (mA/(mA+mB)) x vAi
where mA and mB are the masses of Ball A and Ball B respectively, vAi is the initial velocity of Ball A.
Since both balls have the same mass of 5 kg and Ball A has an initial velocity of 3.5 m/s, the final velocity of Ball B after an elastic collision would be
vf=2 x (5/(5+5)) × 3.5 = 3.5 m/s
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In a perfectly inelastic collision, the two objects stick together after the collision and move with a common final velocity. Since Ball B is initially at rest, its initial velocity is 0 m/s. Therefore, the final velocity of both balls after an inelastic collision would be
vf=(5 x 3.5 + 5 × 0)/(5+5) = 1.75 m/s
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Answers & Comments
Answer:
In a perfectly elastic collision, both momentum and kinetic energy are conserved. The formula for the final velocity of Ball B after an elastic collision is given by:
vf=2x (mA/(mA+mB)) x vAi
where mA and mB are the masses of Ball A and Ball B respectively,
vAi is the initial velocity of Ball A.
Since both balls have the same mass of 5 kg and Ball A has an initial velocity of 3.5 m/s, the final velocity of Ball B after an elastic collision would be
vf=2 x (5/(5+5)) × 3.5 = 3.5 m/s
----
In a perfectly inelastic collision, the two objects stick together after the collision and move with a common final velocity. Since Ball B is initially at rest, its initial velocity is 0 m/s. Therefore, the final velocity of both balls after an inelastic collision would be
vf=(5 x 3.5 + 5 × 0)/(5+5) = 1.75 m/s
Disclaimer
Please give me the brainliest if you're satisfied with the answer. :)