Answer:
1.EFGH is a rhombus 1.Given
2.Diagonals EG, HE 2.Given
3.EF=FG=GH=HE 3.?
4.EG,FH to each 4.?
other
5.EG,FH 5.Definition of
Perpendicular
bisector
6.∆EIH=∆EIF=∆FIG=∆GIH. 6.SAS
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Answer:
1.EFGH is a rhombus 1.Given
2.Diagonals EG, HE 2.Given
3.EF=FG=GH=HE 3.?
4.EG,FH to each 4.?
other
5.EG,FH 5.Definition of
Perpendicular
bisector
6.∆EIH=∆EIF=∆FIG=∆GIH. 6.SAS