9x^2 + 3/4x - √2 = 0
We need to add and subtract to make it in the form
((ax)^2 ± 2*ax*b + b^2) - b^2 + the number given in the Q. = 0
((3x)^2 + 2*3x*1/8 + 1/8^2) - 1/64 - √2 = 0
∴ Ans: b) 1/64 should be added and subtracted to solve the equation by completing the square method.
Hope I helped ☺☻
PS: Pls see whether completing the square method is coming this year or not, was not coming last year
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Answers & Comments
9x^2 + 3/4x - √2 = 0
We need to add and subtract to make it in the form
((ax)^2 ± 2*ax*b + b^2) - b^2 + the number given in the Q. = 0
((3x)^2 + 2*3x*1/8 + 1/8^2) - 1/64 - √2 = 0
∴ Ans: b) 1/64 should be added and subtracted to solve the equation by completing the square method.
Hope I helped ☺☻
PS: Pls see whether completing the square method is coming this year or not, was not coming last year