Answer:
N
2
+3H
→2NH
3
1Vol 3Vol 2Vol
As 3 volume of H
produce 2volume of Nh3
Hence 6 volume of H
produce 4 volume of NH
ans = 4litres
1 mole of Nitrogen requires 3 moles of Hydrogen, i.e. 1L of Nitrogen require 3L of Hydrogen.
1L of Nitrogen → 3L Hydrogen
(x) → 15L Hydrogen
x=3/15
=15 Litres Nitrogen.
1L Nitrogen produces 2L Ammonia, so 5L Nitrogen produces 10L Ammonia.
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Answer:
N
2
+3H
2
→2NH
3
1Vol 3Vol 2Vol
As 3 volume of H
2
produce 2volume of Nh3
3
Hence 6 volume of H
2
produce 4 volume of NH
3
ans = 4litres
Answer:
1 mole of Nitrogen requires 3 moles of Hydrogen, i.e. 1L of Nitrogen require 3L of Hydrogen.
1L of Nitrogen → 3L Hydrogen
(x) → 15L Hydrogen
x=3/15
=15 Litres Nitrogen.
1L Nitrogen produces 2L Ammonia, so 5L Nitrogen produces 10L Ammonia.