Solution:-
Given:- Two ∆s ABC and DEF where AB = DE, BC = EF and angle ABX = angle DEY
To Prove:- ∆ ABC ≈ ∆ DEF
Proof:- angle ABX + angle ABC = angle DEY + angle DEF
angle ABC = angle DEF. [ since angle ABX = angle DEY ]
In ∆s ABC and DEF
AB = DE (Given)
BC = DF (Given)
angle ABC = angle DEF (Proved)
∆s are congruent by SAS criterion
Answer:
if it's helpful to you please mark me as brainliests take care:)
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Verified answer
Solution:-
Given:- Two ∆s ABC and DEF where AB = DE, BC = EF and angle ABX = angle DEY
To Prove:- ∆ ABC ≈ ∆ DEF
Proof:- angle ABX + angle ABC = angle DEY + angle DEF
angle ABC = angle DEF. [ since angle ABX = angle DEY ]
In ∆s ABC and DEF
AB = DE (Given)
BC = DF (Given)
angle ABC = angle DEF (Proved)
∆s are congruent by SAS criterion
Answer:
if it's helpful to you please mark me as brainliests take care:)