Answer:

in ∆ ACP & ∆APB,

angle CAP = angle PAB (angle CAB is bisected by AD)

AP = AP ( common side )

if angle CPD = angle BPD ,

then CPD - 180° = BPD - 180°

angle CPA = angle BPA

By ASA , ∆ CAP is congruent to ∆ BAP.

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