Uday447
Draw PS parallel to BR to meet AC at S. In ΔBCR, P is the mid-point of BC and PS is parallel to BR. ⇒ S is the mid-point of CR ⇒CS = SR ---------------- (1) In ΔAPS, Q is the mid-point of AP and QR is parallel to PS. ⇒ R is the mid-point of AS. ⇒ AR = RS ---------------- (2) From equations (1) and (2), we get AR = RS = SC AC = AR + RS + SC AC = AR + AR + AR AC = 3AR ⇒ AR= 1/3 AC hope it helps
Answers & Comments
In ΔBCR, P is the mid-point of BC and PS is parallel to BR.
⇒ S is the mid-point of CR
⇒CS = SR ---------------- (1)
In ΔAPS, Q is the mid-point of AP and QR is parallel to PS.
⇒ R is the mid-point of AS.
⇒ AR = RS ---------------- (2)
From equations (1) and (2), we get
AR = RS = SC
AC = AR + RS + SC
AC = AR + AR + AR
AC = 3AR
⇒ AR= 1/3 AC
hope it helps