Given Equation is y^3 + 13y^2 + 32y + 20.
= > y^3 + 12y^2 + y^2 + 20y + 12y + 20
= > y^3 + 12y^2 + 20y + y^2 + 12y + 20
= > y(y^2 + 12y + 20) + 1(y^2 + 12y + 20)
= > (y + 1)(y^2 + 12y + 20)
= > (y + 1)(y^2 + 2y + 10y + 20)
= > (y + 1)(y(y + 2) + 10(y + 2))
= > (y + 1)(y + 2)(y + 10).
Therefore, the factors are (y + 1)(y + 2)(y + 10).
Hope this helps!
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Answers & Comments
Given Equation is y^3 + 13y^2 + 32y + 20.
= > y^3 + 12y^2 + y^2 + 20y + 12y + 20
= > y^3 + 12y^2 + 20y + y^2 + 12y + 20
= > y(y^2 + 12y + 20) + 1(y^2 + 12y + 20)
= > (y + 1)(y^2 + 12y + 20)
= > (y + 1)(y^2 + 2y + 10y + 20)
= > (y + 1)(y(y + 2) + 10(y + 2))
= > (y + 1)(y + 2)(y + 10).
Therefore, the factors are (y + 1)(y + 2)(y + 10).
Hope this helps!