solution : from exterior angle property ( If a side of a triangle is produced, then the exterior angle so formed is equal to the sum of the two interior opposite angles )
y = A + B
y = 40° + 35°
y = 75° degree
And from linear angle property (The sum of angles of a linear pair is always equal to 180°)
B + x = 180°
35° + x = 180°
x = 180° - 35°
x = 145°
x= 145° and y = 75°
Note : with the given anlges a triangle can never be an isosceles triangle as the sum of the interior angles will not be equal to 180°.
and if the triangle is not an isosceles triangle the above solution can be considered.
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Verified answer
Given : an isosceleles triangle with AB=AC
A = 40° degree
B = 35° degree
To find : x ,y
solution : from exterior angle property ( If a side of a triangle is produced, then the exterior angle so formed is equal to the sum of the two interior opposite angles )
y = A + B
y = 40° + 35°
y = 75° degree
And from linear angle property (The sum of angles of a linear pair is always equal to 180°)
B + x = 180°
35° + x = 180°
x = 180° - 35°
x = 145°
x= 145° and y = 75°
Note : with the given anlges a triangle can never be an isosceles triangle as the sum of the interior angles will not be equal to 180°.
and if the triangle is not an isosceles triangle the above solution can be considered.
Answer:
As we know that the sum of exterior angle is 180°
Step-by-step explanation:
So,
35°+x = 180°
x = 180°-35°
x = 145°
and for y
40°+35° +y = 180°
75°+y = 180°
y = 180°-75°
y = 105°
Hence, value of x is 145° and y is 105°