The side of a square = Diameter of the semi-circle = a Area of the unshaded region = Area of a square of side ‘a’ + 4(Area of a semi-circle of diameter ‘a’) The horizontal/vertical extent of the white region = 14-3-3 = 8 cm Radius of the semi-circle + side of a square + Radius of the semi-circle = 8 cm 2 (radius of the semi-circle) + side of a square = 8 cm 2a = 8 cm ⇒ a = 4 cm Area of the unshaded region = Area of a square of side 4 cm + 4 (Area of a semi-circle of diameter 4 cm) = (4)2 + 4 X 1/2 π(2)2 = 16 + 8π cm2Read more
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Answer:
The side of a square = Diameter of the semi-circle = a
Area of the unshaded region
= Area of a square of side ‘a’ + 4(Area of a semi-circle of diameter ‘a’)
The horizontal/vertical extent of the white region = 14-3-3 = 8 cm
Radius of the semi-circle + side of a square + Radius of the semi-circle = 8 cm
2 (radius of the semi-circle) + side of a square = 8 cm
2a = 8 cm ⇒ a = 4 cm
Area of the unshaded region
= Area of a square of side 4 cm + 4 (Area of a semi-circle of diameter 4 cm)
= (4)2 + 4 X 1/2 π(2)2 = 16 + 8π cm2
Step-by-step explanation:
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The side of a square = Diameter of the semi-circle = a Area of the unshaded region = Area of a square of side ‘a’ + 4(Area of a semi-circle of diameter ‘a’) The horizontal/vertical extent of the white region = 14-3-3 = 8 cm Radius of the semi-circle + side of a square + Radius of the semi-circle = 8 cm 2 (radius of the semi-circle) + side of a square = 8 cm 2a = 8 cm ⇒ a = 4 cm Area of the unshaded region = Area of a square of side 4 cm + 4 (Area of a semi-circle of diameter 4 cm) = (4)2 + 4 X 1/2 π(2)2 = 16 + 8π cm2Read more