Answer:
AO=OC ,BCZ BOTH IS RADIUS OF THE CIRCLES
LET AO=OC=X
AC²=AO²+OC²...( BY PYTHAGORAS THEOREM)
(7√2)²=X²+X²
(7√2)²=2X²
49*2=2X²
X²=49
X=7
AREA =πR² WHERE ,R=AO=OX=X=7CM
=>22/7*7*7
22*7 =154CM²
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
LET AO=OC=X
AC²=AO²+OC²...( BY PYTHAGORAS THEOREM)
(7√2)²=X²+X²
(7√2)²=2X²
49*2=2X²
X²=49
X=7
AREA =πR² WHERE ,R=AO=OX=X=7CM
=>22/7*7*7
22*7 =154CM²
I HOPE YOU UNDERSTAND DEAR :-)
Answer:
AO=OC ,BCZ BOTH IS RADIUS OF THE CIRCLES
LET AO=OC=X
AC²=AO²+OC²...( BY PYTHAGORAS THEOREM)
(7√2)²=X²+X²
(7√2)²=2X²
49*2=2X²
X²=49
X=7
AREA =πR² WHERE ,R=AO=OX=X=7CM
=>22/7*7*7
22*7 =154CM²