Answer:
They All will beep altogether again at 12:40 pm
Step-by-step explanation:First we will take the least common time when they will ring again by taking their L. C. M: LCM of 16,24 and 18 is 144.
Ao this the common minute when they will ring together.
Now,We will covert 144 minutes into hour :144/60=2.4hours.
So it will again ring altogether at 10:00am +2:40hours =12:40pm.
I hope that now you can understand the logo, Arav. Good luck!
12:24AM
Step-by-step explanation:
First we have to find the prime factors. They are:
16 = 2*2*2*2 = 2^4
18=2*3*3 = 2+3^2
24=2*2*2*3 = 2^3 + 3
Then we multiply the biggest prime factors (exponents) which is
2^4 * 2^3 = 2 × 2 × 2 × 2 × 3 × 3 which is 144
Therefore, the three devices will make a beep 144 minutes in the future, which is 60*2+24, 2 Hr, 24 Min past 10:00 am, which is 12:24AM
If you have any questions, just ask :D
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
They All will beep altogether again at 12:40 pm
Step-by-step explanation:First we will take the least common time when they will ring again by taking their L. C. M: LCM of 16,24 and 18 is 144.
Ao this the common minute when they will ring together.
Now,We will covert 144 minutes into hour :144/60=2.4hours.
So it will again ring altogether at 10:00am +2:40hours =12:40pm.
I hope that now you can understand the logo, Arav. Good luck!
Answer:
12:24AM
Step-by-step explanation:
First we have to find the prime factors. They are:
16 = 2*2*2*2 = 2^4
18=2*3*3 = 2+3^2
24=2*2*2*3 = 2^3 + 3
Then we multiply the biggest prime factors (exponents) which is
2^4 * 2^3 = 2 × 2 × 2 × 2 × 3 × 3 which is 144
Therefore, the three devices will make a beep 144 minutes in the future, which is 60*2+24, 2 Hr, 24 Min past 10:00 am, which is 12:24AM
If you have any questions, just ask :D