like no.d you have to construct a angle PQR , in QR will be 4.5 cm ,but in angle Q you have to construct a angle of 70 degree and also you have to construct a angle of 60 degree in angle R
And in Angle MNP here you also have to construct a angle in which angle M will be your 85 degree and Angle N will be your 115 degree and Angle MN will be your 5 cm respectively
Answers & Comments
To construct: A right angle triangle DEF where DF = 6cm and EF = 4cm
Steps of construction:
(a) Draw a line segment EF = 4cm
(b) At point Q, draw EX LEF
(c) Taking F as centre and radius 6cm, draw an arc (Hypotenuse)
(d) This arc cuts the EX at point D
(e) Join DF
It is the right angled triangle DEF
Answer:
here you have to construct a angle
like no.d you have to construct a angle PQR , in QR will be 4.5 cm ,but in angle Q you have to construct a angle of 70 degree and also you have to construct a angle of 60 degree in angle R
And in Angle MNP here you also have to construct a angle in which angle M will be your 85 degree and Angle N will be your 115 degree and Angle MN will be your 5 cm respectively