Answer:
In △ADC,
)
in triangle ABD
Therefore -----(1)
Substituting values in eq(1)
=
= (As, AB=BC)
=2BC(BC+DB)
=2BC×DC
hence proved...
Step-by-step explanation:
ami jani na kintu ami free na je jartar Bf hoi jabo..
and tui ki amar Friend hobi
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Answers & Comments
Answer:
In △ADC,
in triangle ABD![AB^{2} =AD^{2} +DB^{2} AB^{2} =AD^{2} +DB^{2}](https://tex.z-dn.net/?f=AB%5E%7B2%7D%20%3DAD%5E%7B2%7D%20%2BDB%5E%7B2%7D)
Therefore
-----(1)
Substituting values in eq(1)
=
(As, AB=BC)
=![2BC^{2} +2DB.BC 2BC^{2} +2DB.BC](https://tex.z-dn.net/?f=2BC%5E%7B2%7D%20%2B2DB.BC)
=2BC(BC+DB)
hence proved...
Step-by-step explanation:
ami jani na kintu ami free na je jartar Bf hoi jabo..
and tui ki amar Friend hobi