Verified answer

Answer:

Answer:

\colorbox{\red a \geqslant 15}

\huge\underline\textsf{Explantion:- }

Explantion:-

Let,L = length of the rectangle

B = breadth

A = side of Square

Now, given that

perimeter of rectangle =perimeter of square

\large\underline\textsf{ Formula Used }

Formula Used

=2(l+b)=4a

=l+b=2a

Now, we have given the

Area of rectangle =Are of square-225

LB= a^2

a^2-15^2

\large\underline\textsf{Identity used:- }

Identity used:-

\boxed{(a {}^{2} - b {}^{2} ) = (a + b)(a - b)}

(a

2

−b

2

)=(a+b)(a−b)

Now,

LB =(a+15)(a-15)

Now ,as length is always greater than than the breadth of a rectangle.

\therefore∴ L=a+15 and B=a-15

And ,as the length of any side is always positive so,

\boxed{a - 15 \geqslant 0 = > a \geqslant 15}

a−15⩾0=>a⩾15

L=a +15

& B=a-15

Step-by-step explanation:

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