Answer:
3x−x
2
≥0
x
−3x≤0
x(x−3)≤0
xϵ[0,3]
<4−x
Squarring both sides
<16+x
−8x
As discriminant less than zero so 2x
−11x+16>0 for every xϵR.
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Answer:
3x−x
2
≥0
x
2
−3x≤0
x(x−3)≤0
xϵ[0,3]
3x−x
2
<4−x
Squarring both sides
3x−x
2
<16+x
2
−8x
As discriminant less than zero so 2x
2
−11x+16>0 for every xϵR.
xϵ[0,3]