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Answer:

Let the 2 digits be x and y.

This means that this is a two-digit number.

Given the sum of 2 digits =14.

⟹x+y−14=0………………..(1)

The number is 10x+y

x is in the tens place and y is in the units place.

To make this clear you can refer to the examples:-

73=7∗10+3

54=5∗10+4

67=6∗10+7

So :

10x+y is our assumed number.

Now if we reverse the number what it becomes?

Again few examples will clear your concept.

54⟹45

So 10x+y becomes 10y+x.

10∗5+4⟹10∗4+5

Now this becomes easier.

10x+y when reversed becomes 10y+x.

⟹10y+x=10x+y−18

⟹9y−9x+18=0

⟹x−y−2=0[ Dividing both sides by -9 ]……………(2)

Now adding equation (1) and (2) yields:-

x+y−14+x−y−2=0

⟹2x−16=0

⟹2x=16

⟹x=162

⟹x=8

Now x+y=14

⟹y=14−x

⟹y=14–8=6

Now original number is 10x+y

⟹10∗8+6

⟹80+6=86

The original number is 86.

Hope it helped you.