please solve this question? This is 4 marks question please solve in detail....
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Aasthakatheriya1
Hello... In ∆ DCB tan 60 = DC/ BC √3 = 50 / BC BC = 50/√3 m ---------1 Now taking ∆ ABC, tan 30 = AC/ BC 1 / √3 = h / 50/√3.(by eq.1 ) h = 50 /3 m . I hope it help you...... in picture u see the figure only solution is wrong ... I hope it help you.....
Answers & Comments
In ∆ DCB
tan 60 = DC/ BC
√3 = 50 / BC
BC = 50/√3 m ---------1
Now taking ∆ ABC,
tan 30 = AC/ BC
1 / √3 = h / 50/√3.(by eq.1 )
h = 50 /3 m .
I hope it help you......
in picture u see the figure only solution is wrong ...
I hope it help you.....