Answer:
Hence, finding the net resistance im parallel connection –
1/Rp = 1/R1 + 1/(R2 + R3)
1/Rp = 1/10 + 1/(7+3)
[ We added 7 and 3 as the resistors of 7 ohm and 3 ohm are connected in series ]
1/Rp = 1/10 + 1/10
1/Rp = 2/10
Rp = 10/2
Rp = 5 ohm
Now, finding the net resistance in the series connection –
Rs = R1 + R2 + R3
Rs = 5 + 7 + 3
Rs = 15 ohm
..
QUESTION -
FIND THE EQUIVALENT RESISTANCE BETWEEN THE POINTS (X AND Y).
SOLUTION
Let us carefully observe the above diagram.
The three Ohm and the seven Ohm resistance are in series.
Net resistance between them = 10 Ohm.
Now this 10 Ohm and the other 10 Ohm are In parallel.
So, net resistance between them => ( 10 × 10 ) / ( 10 + 10 )
=> ( 100 / 20 ) ohm = 5 Ohm.
Now resistances between points X and Y -
The following resistances , 7 Ohm, 5 Ohm and 3 OHm are in series .
Hence,
Net resistance = 15 Ohm
ANSWER :
The net resistance between the points X and y is 15 Ohm.
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Answers & Comments
Verified answer
Answer:
Hence, finding the net resistance im parallel connection –
1/Rp = 1/R1 + 1/(R2 + R3)
1/Rp = 1/10 + 1/(7+3)
[ We added 7 and 3 as the resistors of 7 ohm and 3 ohm are connected in series ]
1/Rp = 1/10 + 1/10
1/Rp = 2/10
Rp = 10/2
Rp = 5 ohm
Now, finding the net resistance in the series connection –
Rs = R1 + R2 + R3
Rs = 5 + 7 + 3
Rs = 15 ohm
Verified answer
..
QUESTION -
FIND THE EQUIVALENT RESISTANCE BETWEEN THE POINTS (X AND Y).
SOLUTION
Let us carefully observe the above diagram.
The three Ohm and the seven Ohm resistance are in series.
Net resistance between them = 10 Ohm.
Now this 10 Ohm and the other 10 Ohm are In parallel.
So, net resistance between them => ( 10 × 10 ) / ( 10 + 10 )
=> ( 100 / 20 ) ohm = 5 Ohm.
Now resistances between points X and Y -
The following resistances , 7 Ohm, 5 Ohm and 3 OHm are in series .
Hence,
Net resistance = 15 Ohm
ANSWER :
The net resistance between the points X and y is 15 Ohm.