Answer:
hope it's helpful to you.
comment if you have any doubt in solution
or if it is wrong.
a=dv/dt
dv/dx×dx/dt
a=vdv/dx
From graph
dv/dx=2
a=-2v---------1
( - ) indicates line of graph
Now using eqn of slope
y=mx+c
v=-2+4
( - )is due to negative slope
a=-2(-2x+4)
a=4x-8
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Answers & Comments
Answer:
hope it's helpful to you.
comment if you have any doubt in solution
or if it is wrong.
a=dv/dt
dv/dx×dx/dt
a=vdv/dx
From graph
dv/dx=2
a=-2v---------1
( - ) indicates line of graph
Now using eqn of slope
y=mx+c
v=-2+4
( - )is due to negative slope
a=-2(-2x+4)
a=4x-8