By multiplyinh eqn1 by 3 we get15y +3x= 6xyThen By solving eqn 1 nd 2 we get21y= 7xy21/7=xx=3 By puting value of x in eqn 1 we get 5y +3 =6y 3=y
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By multiplyinh eqn1 by 3 we get
15y +3x= 6xy
Then
By solving eqn 1 nd 2 we get
21y= 7xy
21/7=x
x=3
By puting value of x in eqn 1 we get
5y +3 =6y
3=y