Step-by-step explanation:

Since 'a' and 'b' are symmetrical, we assume a > b

Let k=(a2+b2)/(ab+1)

ab + 1 divides a2+b2

==> ab + 1 also divides (a2+b2)∗b

(a2+b2)∗b=(ab+1)∗a+b3−a

Let c=(b3−a)/(ab+1)

(a2+b2)∗b=(ab+1)∗a+(ab+1)∗c

(a2+b2)/(ab+1)∗b=a+c

bk=(a+c)

a=bk−c

Substitute a=bk−c to c

c=(b3−a)/(ab+1)

=(b3−bk+c)/((bk−c)b+1)

=(b3−bk+c)/(b2∗k−bc+1)

c(b2∗k−bc+1)=(b3−bk+c)

b2∗c∗k−b∗c2+c=b3−bk+c

b2∗c∗k−b∗c2=b3−bk

b∗c∗k−c2=b2−k

b∗c∗k+k=b2+c2

k=(b2+c2)/(bc+1)

If (a, b) is the solution to k=(a2+b2)/(ab+1)

There must exist an order pair (b, c) such that

k=(b2+c2)/(bc+1)

c=(b3−a)/(ab+1)<b3/b2=b

c<b

Photosynthesis, the process by which green plants and certain other organisms transform light energy into chemical energy. During photosynthesis in green plants, light energy is captured and used to convert water, carbon dioxide, and minerals into oxygen and energy-rich organic compounds.