Answer:
1+cotA+tanA=1+1/tanA +tanA
=1+(1+tan²A)/tanA
=1+secA/tanA
(sinA-cosA)(1+secA/tanA)
=(sinA-cosA)(1+cosecA)
=sinA+1-cosA-cotA
dividing this by sec³A-cosec³A
solve this to get answer
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Answer:
1+cotA+tanA=1+1/tanA +tanA
=1+(1+tan²A)/tanA
=1+secA/tanA
(sinA-cosA)(1+secA/tanA)
=(sinA-cosA)(1+cosecA)
=sinA+1-cosA-cotA
dividing this by sec³A-cosec³A
solve this to get answer
PLS MARK IT BRAINLIEST