1.) Angle AOC = 60°
2.) Segment AC = (2)(7)[(sin (60°/2)] = 7
3.) Arc BE = 20°
4.) Segment DC ≈ 8.52
(7 ÷ 2)² + b² = 7²
↓
b² = 7² - (7 ÷ 2)² = 36.75
b ≈ 6.06
(7 ÷ 2)² + (6.06 + 7)² = c²
c² = 182.87049
c ≈ 13.52
DC = 13.52 - BD = 13.52 - 5 = 8.52
5.) Arc AB = (180° - 40°) + (30° ÷ 2) = 140° + 15° = 155°
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ANSWER
1.) Angle AOC = 60°
2.) Segment AC = (2)(7)[(sin (60°/2)] = 7
3.) Arc BE = 20°
4.) Segment DC ≈ 8.52
(7 ÷ 2)² + b² = 7²
↓
b² = 7² - (7 ÷ 2)² = 36.75
↓
b ≈ 6.06
(7 ÷ 2)² + (6.06 + 7)² = c²
↓
c² = 182.87049
↓
c ≈ 13.52
DC = 13.52 - BD = 13.52 - 5 = 8.52
5.) Arc AB = (180° - 40°) + (30° ÷ 2) = 140° + 15° = 155°
#CarryOnLearning