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charita24
@charita24
September 2021
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please solve the 10 sum quickly...it is easy . no spam plz
Answers & Comments
anonymous64
______________________________
Find the sum, invested at 10% compounded annually, on which the interest for third year exceeds the interest of first year by 252.
Let the principal amount (P) be x.
Now, we consider two cases.
P = x
Rate of interest (R) = 10%
Time (n) = 3 years
Therefore,
Compound interest (C.I) = {P (1+R/100)^n}-P
=> C.I.
= {x(1+10/100)³} - x
= {x (100+10/100)³} - x
= {x(110/100)³} - x
= {x(11/10)³} - x
= {1331x/1000} - x
= 1331x - 1000x/1000
= 331x/1000 [Equation 1]
__________________
P = x
R = 10%
n = 1 year
Therefore,
C.I.
= {P (1+ R/100)^n} - P
= {x(1+10/100)¹} - x
= {x(110/100)¹} - x
= {x(11/10)¹} - x
= 11x/10 - x
= 11x-10x/10
= x/10 [Equation 2]
________________
Now, according to question,
331x/1000 = x/10 + 252
=> 331x/1000 - x/10 = 252
=> 331x-100x/1000 = 252
=> 231x/1000 = 252
=> 231x = 252 × 1000
=> 231x = 252000
=> x = 252000/231
=> x = 1091 (approx)
_________________
Hence, the sum is 1091 Rs.
_________________
Your answer is
______________________________
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charita24
please answer the logic for other question in my profile
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Answers & Comments
______________________________
Find the sum, invested at 10% compounded annually, on which the interest for third year exceeds the interest of first year by 252.
Let the principal amount (P) be x.
Now, we consider two cases.
P = x
Rate of interest (R) = 10%
Time (n) = 3 years
Therefore,
Compound interest (C.I) = {P (1+R/100)^n}-P
=> C.I.
= {x(1+10/100)³} - x
= {x (100+10/100)³} - x
= {x(110/100)³} - x
= {x(11/10)³} - x
= {1331x/1000} - x
= 1331x - 1000x/1000
= 331x/1000 [Equation 1]
__________________
P = x
R = 10%
n = 1 year
Therefore,
C.I.
= {P (1+ R/100)^n} - P
= {x(1+10/100)¹} - x
= {x(110/100)¹} - x
= {x(11/10)¹} - x
= 11x/10 - x
= 11x-10x/10
= x/10 [Equation 2]
________________
Now, according to question,
331x/1000 = x/10 + 252
=> 331x/1000 - x/10 = 252
=> 331x-100x/1000 = 252
=> 231x/1000 = 252
=> 231x = 252 × 1000
=> 231x = 252000
=> x = 252000/231
=> x = 1091 (approx)
_________________
Hence, the sum is 1091 Rs.
_________________
Your answer is
______________________________