Given secФ + tanФ = p.
We know that sec^2Ф - tan^2Ф = 1.
We know that a^2 - b^2 = (a + b)(a - b).
= > (secФ + tanФ)(secФ - tanФ) = 1
= > (p)(secФ - tanФ) = 1
= > (secФ - tanФ) = (1/p).
Hope this helps!
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Verified answer
Given secФ + tanФ = p.
We know that sec^2Ф - tan^2Ф = 1.
We know that a^2 - b^2 = (a + b)(a - b).
= > (secФ + tanФ)(secФ - tanФ) = 1
= > (p)(secФ - tanФ) = 1
= > (secФ - tanФ) = (1/p).
Hope this helps!