Final speed of the train, v = 40 km/h = × 40 = 11.11 m/s. Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec. Acceleration of the train. Hence, Acceleration of the train is 0.0185 m/s²
A train starting from a railway station and moving with uniform acceleration attains a speed of 40 km hr-¹ in 10 minutes. Find its acceleration.
Answer:
0.0185 m/s²
Step-by-step explanation:
It's given that a in starting from a railway station and moving with uniform acceleration attains a speed of 40 km hr-¹ in 10 minutes. We need to find out the acceleration of the train.
Let us assume that the acceleration of the train is 'a' m/s².
Here we have zero as the initial velocity of the train, 40 km/hr as the final velocity and 10 minutes as the time taken by train. We will use the formula: (v = u + at) to find out the acceleration of the train.
Before that first we need to convert km/hr into m/s and minutes into seconds, to do so multiply the final velocity by 1000/3600 or 5/18 for m/s and time by 60. Therefore, the final velocity of the train is 11.11 m/s and time is 600 sec. Now, solve further.
Let's dive in!
→ v = u + at
→ 11.11 = 0 + a(600)
→ 11.11 = 600a
→ a = 0.0185
Hence, the acceleration of the train is 0.0185 m/s².
Answers & Comments
Answer:
Final speed of the train, v = 40 km/h = × 40 = 11.11 m/s. Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec. Acceleration of the train. Hence, Acceleration of the train is 0.0185 m/s²
Verified answer
Question:
A train starting from a railway station and moving with uniform acceleration attains a speed of 40 km hr-¹ in 10 minutes. Find its acceleration.
Answer:
0.0185 m/s²
Step-by-step explanation:
It's given that a in starting from a railway station and moving with uniform acceleration attains a speed of 40 km hr-¹ in 10 minutes. We need to find out the acceleration of the train.
Let us assume that the acceleration of the train is 'a' m/s².
Here we have zero as the initial velocity of the train, 40 km/hr as the final velocity and 10 minutes as the time taken by train. We will use the formula: (v = u + at) to find out the acceleration of the train.
Before that first we need to convert km/hr into m/s and minutes into seconds, to do so multiply the final velocity by 1000/3600 or 5/18 for m/s and time by 60. Therefore, the final velocity of the train is 11.11 m/s and time is 600 sec. Now, solve further.
Let's dive in!
→ v = u + at
→ 11.11 = 0 + a(600)
→ 11.11 = 600a
→ a = 0.0185
Hence, the acceleration of the train is 0.0185 m/s².