For real and distinct roots taking discriminant to be zero then by the formula D equal B square minus 4 AC we get
D=(-2(k-1))^2 -4(4)(4)
0=4(k^2+1-2k) - 64
0=4(k^2+1-2k-16)
0=k^2-2k-15
0=k^2+3k-5k-15
0=k(k+3)-5(k+3)
0=(k+3)(k-5)
Therefore
k=5,-3
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Answers & Comments
For real and distinct roots taking discriminant to be zero then by the formula D equal B square minus 4 AC we get
D=(-2(k-1))^2 -4(4)(4)
0=4(k^2+1-2k) - 64
0=4(k^2+1-2k-16)
0=k^2-2k-15
0=k^2+3k-5k-15
0=k(k+3)-5(k+3)
0=(k+3)(k-5)
Therefore
k=5,-3