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14. What are the roots of the equation s²+9=0
a. 3 and 6
b.7 and 5
c. no solutions
d.9 and 2
Answers & Comments
Answer:
No real solutions because the discriminant is negative
The square root of a negative number is not a real number
=
−
3
6
Simplify
Evaluate the exponent
Multiply the numbers
Subtract the numbers
Add zero
Multiply the numbers
=
±
−
3
6
√
2
s=\frac{\pm \sqrt{-36}}{2}
s=2±−36
3
make it clear
the answer is -36
or 3 and 6
the answer is A
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