please look at the attachement and solve the 3 questions asked plaese. Created by rajusetu. Math

please look at the attachement and solve the 3 questions asked plaese...

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May 2021 2 45 Report

please look at the attachement and solve the 3 questions asked
plaese

kaushikravikant Log a / b = log (a - b)
a/b = a - b
a = ab - b²
a (b-1) = b²
a = b²/(b-1)
====================
f(x) = Log [ (1-x)/(1+x) ]
f( (1-x)/(1+x) ) = Log [ {1 - (1-x)/(1+x)} / { 1 + (1-x)/(1+x) } ]
= Log [ 2x / 2 ]
= Log x
===============
$x^{\frac{1}{3}}+y^{\frac{1}{3}}=-z^{\frac{1}{3}}\\\\cubing\\\\x+y+3(xy)^\frac{1}{3}(x^{\frac{1}{3}}+y^{\frac{1}{3}})=-z\\\\x+y+z=-3(xy)^\frac{1}{3}(-z)^{\frac{1}{3}}\\\\\frac{x+y+z}{3}=(xyz)^{\frac{1}{3}}\\\\answer=\frac{1}{3}Log(xyz)$

rajusetu 1 C IS ANSWERE

rajusetu aap galat keya

kaushikravikant Maine solve kar ke answer diya hai

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Verified answer

1)loga- log b= log(a-b)
log a/b=log (a-b) WKT loga/b=loga-logb
a/b=a-b
a=-b²/1-b⇒b²/b-1
option a is correct

2)f(x)=log(1-x)/(1+x)
then f(1-x)/(1+x)
f(1-x)/(1+x)⇒log(1/1 - 1-x/1+x)
(1/1 +1-x/1+x)
log(1+x-1+x)/(1+x+1-x)
log(2x/2)⇒logx
option a is correct

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