Answer:
Equation 1
a-1
b- (-6)
c- (-27)
Discriminant : b²-4ac = (-6)²-4(1)(-27)= 36+108=144
Nature of roots: (9,-3)
Equation 2
a- 1
b- 0
c- (-25)
Discriminant: 0²-4(1)(-25)= 100
Nature: (5,-5)
Equation 3
b- 10
c- 25
Discriminant: 10²-4(1)(25)= 100-100=0
Nature of roots: (-5,-5)
Equation 4
a- 2
b- (-5)
c- 3
Discriminant: (-5)²-4(2)(3)= 25-25= 1
Nature of roots: (-3/2, -1)
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Answer:
Equation 1
a-1
b- (-6)
c- (-27)
Discriminant : b²-4ac = (-6)²-4(1)(-27)= 36+108=144
Nature of roots: (9,-3)
Equation 2
a- 1
b- 0
c- (-25)
Discriminant: 0²-4(1)(-25)= 100
Nature: (5,-5)
Equation 3
a- 1
b- 10
c- 25
Discriminant: 10²-4(1)(25)= 100-100=0
Nature of roots: (-5,-5)
Equation 4
a- 2
b- (-5)
c- 3
Discriminant: (-5)²-4(2)(3)= 25-25= 1
Nature of roots: (-3/2, -1)