Step-by-step explanation:
I hope you understand my answer
Answer:
hii my dear ???❤️❤️hru???❤️❤️
busy or easy ???❤️❤️
uhhh!!! it was the difficultest chapter in maths in mine book!!!⁉️❤️
do u do it easily??
me not ↑↑↑↑↑↑↑↑ (. ❛ ᴗ ❛.)
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Step-by-step explanation:
I hope you understand my answer
Verified answer
Answer:
Solution
Verified by Toppr
We have, L.H.S.=x
3 +y 3 +z 3 −3xyz
=(x+y+z)(x 2 +y 2 +z 2 −xy−yz−zx) [by poynomial identity]
= 21
(x+y+z)(2x 2 +2y 2 +2z
2−2xy−2yz−2zx)= 21
[(x+y+z)(x−y) 2 +(y−z) 2 +(z−x) 2 ]
Hence proved.
Step-by-step explanation:
hii my dear ???❤️❤️hru???❤️❤️
busy or easy ???❤️❤️
uhhh!!! it was the difficultest chapter in maths in mine book!!!⁉️❤️
do u do it easily??
me not ↑↑↑↑↑↑↑↑ (. ❛ ᴗ ❛.)