PLEASE HELP ASAP THIS IS DUE TODAY! Thank you in advance! (NONSENSE WILL BE REPORTED)
1. Problem (1): A point charge of 4|C is 3cm apart from charge 1pC. Find the magnitude of the Coulomb force that one particle exerts on the other and tell if the force is attractive or repulsive.
2. Problem (2): Two like and equal charges are at a radius of 5cm and exert a force of F=9×10-3 N on each other. Find the magnitude of each charge and tell if the force is attractive or repulsive.
3. Problem (3): A point charge of 6nC charge 3nC exerted a force of 1.23×10-6. What is the magnitude of the radius?
1. Problem (1): A point charge of 4|C is 3cm apart from charge 1pC. Find the magnitude of the Coulomb force that one particle exerts on the other and tell if the force is attractive or repulsive.
2. Problem (2): Two like and equal charges are at a radius of 5cm and exert a force of F=9×10-3 N on each other. Find the magnitude of each charge and tell if the force is attractive or repulsive.
3. Problem (3): A point charge of 6nC charge 3nC exerted a force of 1.23×10-6. What is the magnitude of the radius?
Answers & Comments
Answer:
1. The Coulomb force between two point charges can be calculated using Coulomb's law:
F = k * (q1 * q2) / r^2
where F is the force, k is Coulomb's constant (8.99 x 10^9 Nm^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.
Substituting the values, we get:
F = (8.99 x 10^9 Nm^2/C^2) * (4 x 10^-6 C * 1 x 10^-12 C) / (0.03 m)^2
F = 8.99 x 10^9 Nm^2/C^2 * 4 x 10^-6 C * 1 x 10^-12 C / 0.03^2 m^2
F = 4.62 x 10^-7 N
Since the charges are of opposite sign (one positive and one negative), the force is attractive.
2. From Coulomb's law, the force between two charges can be written as:
F = k * (q1 * q2) / r^2
Rearranging, we get:
q1 * q2 = F * r^2 / k
Substituting the given values, we get:
q1 * q2 = 9 x 10^-3 N * (0.05 m)^2 / (8.99 x 10^9 Nm^2/C^2)
q1 * q2 = 1.00 x 10^-12 C^2
Taking the square root of both sides, we get:
q1 = q2 = sqrt(q1 * q2) = sqrt(1.00 x 10^-12 C^2)
q1 = q2 = 1.00 x 10^-6 C
Since the charges are of the same sign (both positive or both negative), the force is repulsive.
3. From Coulomb's law, the force between two charges can be written as:
F = k * (q1 * q2) / r^2
Rearranging, we get:
r^2 = (k * q1 * q2) / F
Substituting the given values, we get:
r^2 = (8.99 x 10^9 Nm^2/C^2) * (6 x 10^-9 C) * (3 x 10^-9 C) / (1.23 x 10^-6 N)
r = sqrt(r^2) = sqrt((8.99 x 10^9 Nm^2/C^2) * (6 x 10^-9 C) * (3 x 10^-9 C) / (1.23 x 10^-6 N))
r = 0.012 m
The magnitude of the radius between the two charges is 0.012 m.