Let p1= mv
p2= mv+20/100 mv
6mv/5
P2=mv'
mv'=6mv/5
mv'=6mv/5v'=6v/5
Substitute value of v'k2=1/2 m(6/5v)^2K2=36/50 mv^2Multiple and divide by 4K2=144/100*1/2mv^2Putting value of k1=1/2 mv^2K2=144/100 k1K2=k1+44/100 k1
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Answers & Comments
Hi mate here is the answer::-✍️✍️✍️
Let p1= mv
p2= mv+20/100 mv
6mv/5
6mv/5
P2=mv'
mv'=6mv/5
mv'=6mv/5v'=6v/5
Substitute value of v'k2=1/2 m(6/5v)^2K2=36/50 mv^2Multiple and divide by 4K2=144/100*1/2mv^2Putting value of k1=1/2 mv^2K2=144/100 k1K2=k1+44/100 k1
So K1 increased by 44%
Hope it helps you ❣️☑️☑️