When we dividep(x)=x^3+8x^2+17x+ax by (x+1) and (x+2) we get the same remainder So, P(-1)=P(-2) (-2)^3+8(-2)^2+17(-2)+a(-2)=(-1)^3+8(-1)^2+17(-1)+a(-1) -8+32-34-2a=-1+8-17-a -8-2-2a=7-17-a -10-2a=-10-a -2a+a= -10+10 -a=0 So a is 0
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When we dividep(x)=x^3+8x^2+17x+ax by (x+1) and (x+2) we get the same remainder
So,
P(-1)=P(-2)
(-2)^3+8(-2)^2+17(-2)+a(-2)=(-1)^3+8(-1)^2+17(-1)+a(-1)
-8+32-34-2a=-1+8-17-a
-8-2-2a=7-17-a
-10-2a=-10-a
-2a+a= -10+10
-a=0
So a is 0
HOPE IT WILL HELP U
PLEASE MARK IT AS BRAINLIEST ANSWER