Verified answer

Answer:

Let ABCD is a rhombus AC and BD are its diagonals which bisect each other at right angles at O.

AC= 16 cm and BD = 12 cm

∴

AO=16/2=8cm

BO=12/2=6 cm

Now, in right

△AOB

AB2=AO2+BO2

(Pythagoras Theorem)

=(8)2+(6)2

=64+36

=100

=(10)2

∴AB=10cm

But all the sides of a rhombus are equal

∴AB=10cm

pls mark me as brainalist

All the sides of a rhombus are equal in length

The diagonals of a rhombus intersect at 90°

The send the sides of a rhombus form right triangles

In ∆AOB :-

AB² = AO²+OB²

=8²+6²

=√100

=10 cm

AB= 10cm

Therefore, the length of each side of a rhombus is 10cm