Answer:
(a) It is second class lever
(b) Diagram is above
Load and effort are in opposite direction
M.A=
effortrequired
Loadlifted
=
E
L
5
9
=1.8
V.R=
distancemovedbyload
distancemovedbyeffort
η
M.A
(c) If efficiency is η=100%=1
η=
V.R
1
1.8
(d) If efficiency is η=50%=0.5
0.5
=3.6
Answer for option a) is attached above.
c) mechanical age is
M.A = effect arm / load arm = 9 cm / 5 cm
c = 1.8
Relation between MA efficiency and V.R is
M.A = n×V.R
M.A = V.R = 1.8 ( n=100% = 1 )
D) When efficiency reduces to 50%, its mechanical advantage reduces however, its velocity ratio remains the same. So,
M.A. = 0.5 x 1.8 = 0.9
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Answers & Comments
Answer:
(a) It is second class lever
(b) Diagram is above
Load and effort are in opposite direction
M.A=
effortrequired
Loadlifted
=
E
L
=
5
9
=1.8
V.R=
distancemovedbyload
distancemovedbyeffort
=
η
M.A
(c) If efficiency is η=100%=1
η=
V.R
M.A
V.R=
1
1.8
=1.8
(d) If efficiency is η=50%=0.5
η=
V.R
M.A
V.R=
0.5
1.8
=3.6
Answer for option a) is attached above.
c) mechanical age is
M.A = effect arm / load arm = 9 cm / 5 cm
c = 1.8
Relation between MA efficiency and V.R is
M.A = n×V.R
M.A = V.R = 1.8 ( n=100% = 1 )
D) When efficiency reduces to 50%, its mechanical advantage reduces however, its velocity ratio remains the same. So,
M.A. = 0.5 x 1.8 = 0.9