Answer:
I think this answer is correct
Explanation:
Let the speed of each bus = v km/h The distance between the nearest buses
plying on either car vT km.......(i)
For buses going from town A to B: Relative speed of bus in the direction of
motion of man = (v-20)
Buses plying in this direction go past the cyclist after every 18 min. Therefore,
separation between the buses = >
(v - 20)x(18/60)
From (i)--> (v-20)(18/60) = VT...... (2)
For buses coming from B to A: The relative velocity of bus with respect to
man = (v+ 20) Buses coming from town B past the cyclist after every 6 min,
(v + 20)x(6/60) = vT........(3)
Solving (2) and (3),we can use any method to solve equations, we get-->
V = 40 km/h
T = 2/30 h
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Answers & Comments
Answer:
I think this answer is correct
Explanation:
Let the speed of each bus = v km/h The distance between the nearest buses
plying on either car vT km.......(i)
For buses going from town A to B: Relative speed of bus in the direction of
motion of man = (v-20)
Buses plying in this direction go past the cyclist after every 18 min. Therefore,
separation between the buses = >
(v - 20)x(18/60)
From (i)--> (v-20)(18/60) = VT...... (2)
For buses coming from B to A: The relative velocity of bus with respect to
man = (v+ 20) Buses coming from town B past the cyclist after every 6 min,
(v + 20)x(6/60) = vT........(3)
Solving (2) and (3),we can use any method to solve equations, we get-->
V = 40 km/h
T = 2/30 h
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THANKS FOR THANKING MY ANS