1.
[tex]a = \pi {r}^{2} \\ = \pi( { 8cm})^{2} \\ = 64\pi {cm}^{2} [/tex]
2.
[tex]a = \pi {r}^{2} \\ = \pi( { 12dm})^{2} \\ = 144\pi {dm}^{2} [/tex]
3.
[tex]a = \pi {r}^{2} \\ = \pi( { 9m})^{2} \\ = 81\pi {m}^{2} [/tex]
4.
[tex]a = \pi {r}^{2} \\ = \pi( { 10cm})^{2} \\ = 100\pi {cm}^{2} [/tex]
5.
[tex]a = \pi {r}^{2} \\ = \pi( { 16cm})^{2} \\ = 256\pi {cm}^{2} [/tex]
The radius of the circle is the half of diameter. Items number 3 and 4, is an example of diameter of a circle. In order to find the radius, just divide it by 2. Since the half of diameter is the radius.
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Answers & Comments
1.
[tex]a = \pi {r}^{2} \\ = \pi( { 8cm})^{2} \\ = 64\pi {cm}^{2} [/tex]
2.
[tex]a = \pi {r}^{2} \\ = \pi( { 12dm})^{2} \\ = 144\pi {dm}^{2} [/tex]
3.
[tex]a = \pi {r}^{2} \\ = \pi( { 9m})^{2} \\ = 81\pi {m}^{2} [/tex]
4.
[tex]a = \pi {r}^{2} \\ = \pi( { 10cm})^{2} \\ = 100\pi {cm}^{2} [/tex]
5.
[tex]a = \pi {r}^{2} \\ = \pi( { 16cm})^{2} \\ = 256\pi {cm}^{2} [/tex]
The radius of the circle is the half of diameter. Items number 3 and 4, is an example of diameter of a circle. In order to find the radius, just divide it by 2. Since the half of diameter is the radius.