Explanation:
2
1
H⟶
4
He
Mass defect =m(
He)−2m(
H)
=4.0026−2×2.0141
=−0.0256units
=−0.0256×10
−3
kgunit
∴BE=△mc
=0.0256×10
×(2.998×10
8
)
=2.3×10
12
J
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Answers & Comments
Explanation:
2
1
2
H⟶
2
4
He
Mass defect =m(
2
4
He)−2m(
1
2
H)
=4.0026−2×2.0141
=−0.0256units
=−0.0256×10
−3
kgunit
∴BE=△mc
2
=0.0256×10
−3
×(2.998×10
8
)
2
=2.3×10
12
J